Calculating percentage of CaCO3 by mass in the tablet
1. amount = conc x vol = 0.30 x 0.0111 = 0.00333 mol
2. Moles of HCl left in 10.0 cm3 = 0.00333 mol
3. Moles of HCl left in 100 cm3 of solution = 0.00333 x 10 = 0.0333
4. Moles of HCl that reacted with the indigestion tablet = 0.05 - 0.0333 = 0.0167
5. Moles of CaCO3 = 0.0167/2 = 0.00835
6. Mass of CaCO3 = 0.00835 x 100 = 0.835 g
7. Percentage of CaCO3 by mass in the tablet = 0.835/0.950 x 100 = 87.9 %