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Topic 3: Redox I
3.2 Redox Reactions
3.2.1 Balancing Redox Equations
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What is the mnemonic for remembering oxidation and reduction in terms of electron transfer?
OIL RIG
The oxidation half-equation for iron is
F
e
→
F
e
2
+
+
Fe → Fe²⁺ +
F
e
→
F
e
2
+
+
2
e
−
2e⁻
2
e
−
Match the process with its electron change and example:
Oxidation ↔️ Loss;
F
e
→
F
e
2
+
+
Fe → Fe^{2 + } +
F
e
→
F
e
2
+
+
2
e
−
2e^ -
2
e
−
Reduction ↔️ Gain;
C
u
2
+
+
Cu^{2 + } +
C
u
2
+
+
2
e
−
→
C
u
2e^ - → Cu
2
e
−
→
C
u
In the reaction between iron and copper(II) ions, iron is oxidized and copper(II) ions are
reduced
.
Monoatomic ions have an oxidation state equal to their
charge
What is the oxidation state of oxygen in most compounds?
-2
In
H
2
O
H₂O
H
2
O
, hydrogen has an oxidation state of +1 and oxygen has -2.
Steps to write half-equations
1️⃣ Identify oxidation and reduction
2️⃣ Write each process as a separate equation
3️⃣ Balance atoms and charge by adding electrons
Match the process with its half-equation:
Oxidation ↔️
Z
n
→
Z
n
2
+
+
Zn → Zn^{2 + } +
Z
n
→
Z
n
2
+
+
2
e
−
2e^ -
2
e
−
Reduction ↔️
C
u
2
+
+
Cu^{2 + } +
C
u
2
+
+
2
e
−
→
C
u
2e^ - → Cu
2
e
−
→
C
u
What is the usual oxidation state of oxygen except in peroxides and fluorides?
-2
Half-equations represent either the oxidation or reduction process in a redox reaction
separately
Write the half-equation for the oxidation process of iron.
F
e
→
F
e
2
+
+
Fe → Fe²⁺ +
F
e
→
F
e
2
+
+
2
e
−
2e⁻
2
e
−
Write the half-equation for the reduction process of copper(II) ions.
C
u
2
+
+
Cu²⁺ +
C
u
2
+
+
2
e
−
→
C
u
2e⁻ → Cu
2
e
−
→
C
u
Half-equations represent either the oxidation or
reduction
process in a redox reaction separately.
To balance the number of atoms and charge in a half-equation, add
electrons
What is the first step in balancing atoms other than oxygen and hydrogen in a half-equation?
Identify the atoms
To balance oxygen atoms in a half-equation, add
water
Oxidation involves the loss of
electrons
.
The mnemonic 'OIL RIG' stands for Oxidation Is Loss, Reduction Is
Gain
What is the oxidation state of a free element?
0
The sum of oxidation states in a
neutral compound
is always 0.
What is the typical oxidation state of oxygen in a compound?
-2
What is the typical oxidation state of hydrogen in a compound?
+1
Half-equations represent either the oxidation or reduction part of a
redox
reaction separately.
Write the oxidation half-equation for zinc.
Z
n
→
Z
n
2
+
+
Zn → Zn^{2 + } +
Z
n
→
Z
n
2
+
+
2
e
−
2e^ -
2
e
−
Write the reduction half-equation for copper(II) ions.
C
u
2
+
+
Cu^{2 + } +
C
u
2
+
+
2
e
−
→
C
u
2e^ - → Cu
2
e
−
→
C
u
Balancing atoms other than oxygen and
hydrogen
involves multiplying compounds by coefficients.
To balance atoms other than oxygen and hydrogen, multiply the appropriate compounds or ions by
coefficients
What is added to balance oxygen atoms in a half-equation?
H
2
O
H_{2}O
H
2
O
What is the first step to balance oxygen atoms in a half-equation?
Identify fewer oxygen atoms
To balance oxygen atoms, add water molecules (
H
2
O
H_{2}O
H
2
O
) to the side with fewer oxygen atoms
Oxygen atoms are balanced by adding water molecules to the side with more oxygen atoms
False
How many water molecules are added to balance the oxygen atoms in the half-equation
M
n
O
4
−
→
M
n
2
+
MnO_{4}^{ - } → Mn^{2 + }
M
n
O
4
−
→
M
n
2
+
?
4
To balance the half-equation
M
n
O
4
−
→
M
n
2
+
MnO_{4}^{ - } → Mn^{2 + }
M
n
O
4
−
→
M
n
2
+
, we add 4 water molecules to the product
Hydrogen atoms are balanced by adding hydrogen ions (
H
+
H⁺
H
+
) to the side with fewer hydrogen atoms
In the half-equation MnO_{4}^{ - } → Mn^{2 + } + 4H_{2}O</latex>, how many hydrogen ions are needed to balance the hydrogen atoms?
8
The balanced half-equation for hydrogen atoms is
M
n
O
4
−
+
MnO_{4}^{ - } +
M
n
O
4
−
+
8
H
+
→
M
n
2
+
+
8H⁺ → Mn^{2 + } +
8
H
+
→
M
n
2
+
+
4
H
2
O
4H_{2}O
4
H
2
O
where
8
H
+
8H⁺
8
H
+
balances the hydrogen
To balance charges in a half-equation, add
electrons
to the side with the more positive charge
In the half-equation MnO_{4}^{ - } + 8H⁺ → Mn^{2 + } + 4H_{2}O</latex>, what is the total charge on the reactant side?
+7
To balance the charges in the half-equation
M
n
O
4
−
+
MnO_{4}^{ - } +
M
n
O
4
−
+
8
H
+
→
M
n
2
+
+
8H⁺ → Mn^{2 + } +
8
H
+
→
M
n
2
+
+
4
H
2
O
4H_{2}O
4
H
2
O
, we add 5 electrons to the reactant
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