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Pure Core
2. Matrices
2.3 Inverses of Matrices
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Cards (52)
What is the condition for a matrix
A
A
A
to have an inverse
A
−
1
A^{ - 1}
A
−
1
?
A
×
A
−
1
=
A \times A^{ - 1} =
A
×
A
−
1
=
I
I
I
A matrix
A
A
A
is invertible only if it is non-singular
Invertible matrices have a determinant equal to zero.
False
What must the determinant of a matrix be for it to have an inverse?
≠
0
≠ 0
=
0
Singular matrices have a determinant equal to
zero
The matrix
A
=
A =
A
=
[
2
1
1
1
]
\begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}
[
2
1
1
1
]
has an inverse because its determinant is 1.
Match the type of matrix with its property:
Non-singular matrix ↔️ Determinant ≠ 0
Singular matrix ↔️ Determinant = 0
Which type of matrices are non-invertible?
Singular matrices
A matrix with a determinant of 0 is invertible.
False
A matrix with a non-zero determinant is called
non-singular
What is the determinant of the matrix
A
=
A =
A
=
[
2
1
1
1
]
\begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}
[
2
1
1
1
]
?
1
Under what condition does a matrix
A
A
A
have an inverse
A
−
1
A^{ - 1}
A
−
1
?
If A is non-singular
Non-singular matrices have a determinant equal to zero.
False
What is the determinant of a non-invertible matrix?
0
A matrix is invertible if its determinant is not equal to
zero
What is the formula to calculate the inverse of a 2x2 matrix
A
=
A =
A
=
[
a
b
c
d
]
\begin{bmatrix} a & b \\ c & d \end{bmatrix}
[
a
c
b
d
]
?
A
−
1
=
A^{ - 1} =
A
−
1
=
1
∣
A
∣
[
d
−
b
−
c
a
]
\frac{1}{|A|} \begin{bmatrix} d & - b \\ - c & a \end{bmatrix}
∣
A
∣
1
[
d
−
c
−
b
a
]
Steps to calculate the inverse of a 2x2 matrix
1️⃣ Find the determinant|A| = ad - bc</latex>
2️⃣ Form the adjugate by swapping
a
a
a
and
d
d
d
, and negating
b
b
b
and
c
c
c
3️⃣ Multiply the adjugate by
1
∣
A
∣
\frac{1}{|A|}
∣
A
∣
1
A matrix
A
A
A
has an inverse if
A
×
A
−
1
=
A \times A^{ - 1} =
A
×
A
−
1
=
A
−
1
×
A
=
A^{ - 1} \times A =
A
−
1
×
A
=
I
I
I
.
What is the determinant of a2x2 matrix used in the inverse formula?
∣
A
∣
=
|A| =
∣
A
∣
=
a
d
−
b
c
ad - bc
a
d
−
b
c
How do you calculate the minor
M
i
j
M_{ij}
M
ij
in a matrix
A
A
A
?
Determinant of 2x2 submatrix
The cofactor matrix
C
C
C
applies signs to the minor matrix according to a specific pattern
The adjoint matrix is obtained by transposing the
cofactor
matrix.
What formula is used to calculate the inverse of a matrix
A
A
A
using the adjoint method?
A
−
1
=
A^{ - 1} =
A
−
1
=
1
∣
A
∣
a
d
j
(
A
)
\frac{1}{|A|} adj(A)
∣
A
∣
1
a
d
j
(
A
)
Steps to calculate the inverse of a 3x3 matrix using the adjoint method
1️⃣ Find the determinant
2️⃣ Find the minor matrix
3️⃣ Form the cofactor matrix
4️⃣ Find the adjoint matrix
5️⃣ Calculate the inverse
If the determinant of a matrix is 0, the matrix has no
inverse
.
The cofactor matrix
C
C
C
applies alternating signs to the minor matrix in a specific pattern
What is the final step in calculating the inverse of a matrix using the adjoint method?
Multiply adjoint by
1
∣
A
∣
\frac{1}{|A|}
∣
A
∣
1
Steps for calculating the inverse of a 3x3 matrix using the adjoint method
1️⃣ Find the determinant of the matrix
∣
A
∣
|A|
∣
A
∣
2️⃣ Calculate the minor matrix
M
M
M
3️⃣ Create the cofactor matrix
C
C
C
4️⃣ Find the adjoint matrix
a
d
j
(
A
)
adj(A)
a
d
j
(
A
)
by transposing
C
C
C
5️⃣ Multiply the adjoint matrix by
1
∣
A
∣
\frac{1}{|A|}
∣
A
∣
1
to get the inverse
A
−
1
A^{ - 1}
A
−
1
The inverse of a matrix
A
A
A
is calculated using the formula
A
−
1
=
A^{ - 1} =
A
−
1
=
1
∣
A
∣
a
d
j
(
A
)
\frac{1}{|A|} adj(A)
∣
A
∣
1
a
d
j
(
A
)
, where |A|</latex> is the determinant
If the determinant of a matrix
A
A
A
is zero, the matrix has no inverse.
The minor
M
i
j
M_{ij}
M
ij
of an element
a
i
j
a_{ij}
a
ij
in a matrix
A
A
A
is the determinant of the 2x2 submatrix obtained by removing the
i
i
i
-th row and
j
j
j
-th column
The cofactor matrix is created by applying alternating signs to the
minor matrix
.
The adjoint matrix
a
d
j
(
A
)
adj(A)
a
d
j
(
A
)
is the transpose of the cofactor matrix.
Match the type of matrix with its property:
Non-singular matrix ↔️ Determinant
≠
0
≠ 0
=
0
Singular matrix ↔️ Determinant
=
=
=
0
0
0
Invertible matrix ↔️ Has a non-zero determinant
Non-invertible matrix ↔️ Has a zero determinant
The inverse of a matrix
A
A
A
is denoted as
A
−
1
A^{ - 1}
A
−
1
, and it satisfies the condition A \times A^{ - 1} = A^{ - 1} \times A = I</latex>.
A matrix is invertible if and only if it is
non-singular
.
What is the determinant of the matrix
A
=
A =
A
=
[
2
1
1
1
]
\begin{bmatrix} 2 & 1 \\ 1 & 1 \end{bmatrix}
[
2
1
1
1
]
?
1
A matrix with a non-zero determinant has an
inverse
.
What condition must a matrix satisfy to be invertible?
Non-singular
Match the type of matrix with its determinant condition:
Invertible matrix ↔️ Determinant ≠ 0
Non-invertible matrix ↔️ Determinant = 0
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