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1. Kinematics
1.2 Dynamics
2.2 Work, Energy, and Power
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Cards (157)
What is work done measured in?
Joules
Work done is a
scalar quantity
When the force is constant and parallel to the displacement, the formula for work done is
W = Fd
What formula is used to calculate work done by a variable force?
W
=
W =
W
=
∫
a
b
F
⋅
d
s
\int_{a}^{b} F \cdot ds
∫
a
b
F
⋅
d
s
The formula
W
=
W =
W
=
F
d
Fd
F
d
is used for work done by a variable force
False
Match the force type with its work done calculation:
Constant Force ↔️
W
=
W =
W
=
F
d
Fd
F
d
Variable Force ↔️
W
=
W =
W
=
∫
a
b
F
⋅
d
s
\int_{a}^{b} F \cdot ds
∫
a
b
F
⋅
d
s
Potential energy is the stored energy an object has due to its
position
What is the formula for gravitational potential energy?
P
E
=
PE =
PE
=
m
g
h
mgh
m
g
h
Elastic potential energy is calculated using the formula
P
E
=
PE =
PE
=
1
2
k
x
2
\frac{1}{2} kx^{2}
2
1
k
x
2
What is the formula for kinetic energy?
KE = \frac{1}{2} mv^{2}</latex>
Kinetic energy is the energy of
motion
Match the concept with its definition and formula:
Power ↔️ Rate at which work is done;
P
=
P =
P
=
W
t
\frac{W}{t}
t
W
Work Done ↔️ Energy transferred by a force;
W
=
W =
W
=
F
d
Fd
F
d
Power is measured in units called
Watts
What is the formula for power?
P
=
P =
P
=
W
t
\frac{W}{t}
t
W
Power is a
scalar
quantity
Arrange the following in the correct order for calculating work done by a variable force:
1️⃣ Identify the force function
2️⃣ Set the limits of integration
3️⃣ Perform the integration
What is the formula for work done when a constant force is applied?
W
=
W =
W
=
F
d
Fd
F
d
In the formula for work done,
d
d
d
represents the distance
The work done by a constant force is calculated using the formula
W = Fd
</latex>.
Match the type of potential energy with its formula and key variables:
Gravitational Potential Energy ↔️
P
E
=
PE =
PE
=
m
g
h
mgh
m
g
h
||| Mass (
m
m
m
), Gravitational Acceleration (
g
g
g
), Height (
h
h
h
)
Elastic Potential Energy ↔️
P
E
=
PE =
PE
=
1
2
k
x
2
\frac{1}{2} kx^{2}
2
1
k
x
2
||| Spring Constant (
k
k
k
), Displacement (
x
x
x
)
Electric Potential Energy ↔️
P
E
=
PE =
PE
=
q
V
qV
q
V
||| Charge (
q
q
q
), Electric Potential (
V
V
V
)
The formula for gravitational potential energy is
P
E
=
PE =
PE
=
m
g
h
mgh
m
g
h
What is kinetic energy measured in?
Joules (J)
The formula for kinetic energy is KE = \frac{1}{2}
mv^{2}
</latex>.
In the kinetic energy formula,
v
v
v
represents the object's velocity
What is the formula for power?
P
=
P =
P
=
W
t
\frac{W}{t}
t
W
Match the concept with its definition and formula:
Power ↔️ Rate at which work is done |||
P
=
P =
P
=
W
t
\frac{W}{t}
t
W
Work Done ↔️ Energy transferred by a force |||
W
=
W =
W
=
F
d
Fd
F
d
Energy ↔️ Capacity to do work ||| Varies depending on the type
Power is measured in
Watts
What does the Work-Energy Principle state?
Net work equals change in KE
The Work-Energy Principle is expressed as
W
n
e
t
=
W_{net} =
W
n
e
t
=
Δ
K
E
\Delta KE
Δ
K
E
.
Steps to solve the example problem using the Work-Energy Principle
1️⃣ Calculate the work done:
W
=
W =
W
=
F
d
=
Fd =
F
d
=
200
J
200 J
200
J
2️⃣ Use the work-energy principle:
Δ
K
E
=
\Delta KE =
Δ
K
E
=
W
=
W =
W
=
200
J
200 J
200
J
3️⃣ Calculate the final kinetic energy:
K
E
f
=
KE_{f} =
K
E
f
=
210
J
210 J
210
J
4️⃣ Find the final speed:
v
f
≈
9.17
m
/
s
v_{f} \approx 9.17 m / s
v
f
≈
9.17
m
/
s
What is the formula for work done by a force moving an object?
W
=
W =
W
=
F
d
Fd
F
d
The kinetic energy of an object is measured in
Joules
What does the Work-Energy Principle state?
Work equals change in KE
The Work-Energy Principle can be expressed as W = \Delta KE = KE_{f} - KE_{i}</latex>, where
K
E
f
KE_{f}
K
E
f
and
K
E
i
KE_{i}
K
E
i
are the final and initial kinetic energies
In the example problem, what is the work done on the 5 kg block?
200 J
Steps to solve the example problem using the Work-Energy Principle:
1️⃣ Calculate the work done: W = Fd</latex>
2️⃣ Use the Work-Energy Principle:
Δ
K
E
=
\Delta KE =
Δ
K
E
=
W
W
W
3️⃣ Calculate the final kinetic energy:
K
E
f
=
KE_{f} =
K
E
f
=
K
E
i
+
KE_{i} +
K
E
i
+
Δ
K
E
\Delta KE
Δ
K
E
4️⃣ Find the final speed:
v
f
=
v_{f} =
v
f
=
2
×
K
E
f
m
\sqrt{\frac{2 \times KE_{f}}{m}}
m
2
×
K
E
f
The final speed of the block in the example problem is approximately
9.17 m/s
.
Match the concept with its definition, formula, and unit:
Work ↔️ Energy transferred by a force moving an object |||
W
=
W =
W
=
F
d
Fd
F
d
||| Joules (J)
Kinetic Energy ↔️ Energy possessed by an object due to its motion |||
K
E
=
KE =
K
E
=
1
2
m
v
2
\frac{1}{2}mv^{2}
2
1
m
v
2
||| Joules (J)
What is the definition of work done?
Energy transferred by a force
The formula for work done by a constant force is
W
=
W =
W
=
F
d
Fd
F
d
, while for a variable force it is W = \int_{a}^{b} F \cdot ds</latex>.distance
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